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Diffstat (limited to 'gl/memchr.c')
-rw-r--r-- | gl/memchr.c | 201 |
1 files changed, 0 insertions, 201 deletions
diff --git a/gl/memchr.c b/gl/memchr.c deleted file mode 100644 index d44ad6d..0000000 --- a/gl/memchr.c +++ /dev/null | |||
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1 | /* Copyright (C) 1991, 1993, 1996, 1997, 1999, 2000, 2003, 2004, 2006 Free | ||
2 | Software Foundation, Inc. | ||
3 | |||
4 | Based on strlen implementation by Torbjorn Granlund (tege@sics.se), | ||
5 | with help from Dan Sahlin (dan@sics.se) and | ||
6 | commentary by Jim Blandy (jimb@ai.mit.edu); | ||
7 | adaptation to memchr suggested by Dick Karpinski (dick@cca.ucsf.edu), | ||
8 | and implemented by Roland McGrath (roland@ai.mit.edu). | ||
9 | |||
10 | NOTE: The canonical source of this file is maintained with the GNU C Library. | ||
11 | Bugs can be reported to bug-glibc@prep.ai.mit.edu. | ||
12 | |||
13 | This program is free software; you can redistribute it and/or modify it | ||
14 | under the terms of the GNU General Public License as published by the | ||
15 | Free Software Foundation; either version 2, or (at your option) any | ||
16 | later version. | ||
17 | |||
18 | This program is distributed in the hope that it will be useful, | ||
19 | but WITHOUT ANY WARRANTY; without even the implied warranty of | ||
20 | MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the | ||
21 | GNU General Public License for more details. | ||
22 | |||
23 | You should have received a copy of the GNU General Public License | ||
24 | along with this program; if not, write to the Free Software Foundation, | ||
25 | Inc., 51 Franklin Street, Fifth Floor, Boston, MA 02110-1301, USA. */ | ||
26 | |||
27 | #ifndef _LIBC | ||
28 | # include <config.h> | ||
29 | #endif | ||
30 | |||
31 | #include <string.h> | ||
32 | |||
33 | #include <stddef.h> | ||
34 | |||
35 | #if defined _LIBC | ||
36 | # include <memcopy.h> | ||
37 | #else | ||
38 | # define reg_char char | ||
39 | #endif | ||
40 | |||
41 | #include <limits.h> | ||
42 | |||
43 | #if HAVE_BP_SYM_H || defined _LIBC | ||
44 | # include <bp-sym.h> | ||
45 | #else | ||
46 | # define BP_SYM(sym) sym | ||
47 | #endif | ||
48 | |||
49 | #undef memchr | ||
50 | #undef __memchr | ||
51 | |||
52 | /* Search no more than N bytes of S for C. */ | ||
53 | void * | ||
54 | __memchr (void const *s, int c_in, size_t n) | ||
55 | { | ||
56 | const unsigned char *char_ptr; | ||
57 | const unsigned long int *longword_ptr; | ||
58 | unsigned long int longword, magic_bits, charmask; | ||
59 | unsigned reg_char c; | ||
60 | int i; | ||
61 | |||
62 | c = (unsigned char) c_in; | ||
63 | |||
64 | /* Handle the first few characters by reading one character at a time. | ||
65 | Do this until CHAR_PTR is aligned on a longword boundary. */ | ||
66 | for (char_ptr = (const unsigned char *) s; | ||
67 | n > 0 && (size_t) char_ptr % sizeof longword != 0; | ||
68 | --n, ++char_ptr) | ||
69 | if (*char_ptr == c) | ||
70 | return (void *) char_ptr; | ||
71 | |||
72 | /* All these elucidatory comments refer to 4-byte longwords, | ||
73 | but the theory applies equally well to any size longwords. */ | ||
74 | |||
75 | longword_ptr = (const unsigned long int *) char_ptr; | ||
76 | |||
77 | /* Bits 31, 24, 16, and 8 of this number are zero. Call these bits | ||
78 | the "holes." Note that there is a hole just to the left of | ||
79 | each byte, with an extra at the end: | ||
80 | |||
81 | bits: 01111110 11111110 11111110 11111111 | ||
82 | bytes: AAAAAAAA BBBBBBBB CCCCCCCC DDDDDDDD | ||
83 | |||
84 | The 1-bits make sure that carries propagate to the next 0-bit. | ||
85 | The 0-bits provide holes for carries to fall into. */ | ||
86 | |||
87 | /* Set MAGIC_BITS to be this pattern of 1 and 0 bits. | ||
88 | Set CHARMASK to be a longword, each of whose bytes is C. */ | ||
89 | |||
90 | magic_bits = 0xfefefefe; | ||
91 | charmask = c | (c << 8); | ||
92 | charmask |= charmask << 16; | ||
93 | #if 0xffffffffU < ULONG_MAX | ||
94 | magic_bits |= magic_bits << 32; | ||
95 | charmask |= charmask << 32; | ||
96 | if (8 < sizeof longword) | ||
97 | for (i = 64; i < sizeof longword * 8; i *= 2) | ||
98 | { | ||
99 | magic_bits |= magic_bits << i; | ||
100 | charmask |= charmask << i; | ||
101 | } | ||
102 | #endif | ||
103 | magic_bits = (ULONG_MAX >> 1) & (magic_bits | 1); | ||
104 | |||
105 | /* Instead of the traditional loop which tests each character, | ||
106 | we will test a longword at a time. The tricky part is testing | ||
107 | if *any of the four* bytes in the longword in question are zero. */ | ||
108 | while (n >= sizeof longword) | ||
109 | { | ||
110 | /* We tentatively exit the loop if adding MAGIC_BITS to | ||
111 | LONGWORD fails to change any of the hole bits of LONGWORD. | ||
112 | |||
113 | 1) Is this safe? Will it catch all the zero bytes? | ||
114 | Suppose there is a byte with all zeros. Any carry bits | ||
115 | propagating from its left will fall into the hole at its | ||
116 | least significant bit and stop. Since there will be no | ||
117 | carry from its most significant bit, the LSB of the | ||
118 | byte to the left will be unchanged, and the zero will be | ||
119 | detected. | ||
120 | |||
121 | 2) Is this worthwhile? Will it ignore everything except | ||
122 | zero bytes? Suppose every byte of LONGWORD has a bit set | ||
123 | somewhere. There will be a carry into bit 8. If bit 8 | ||
124 | is set, this will carry into bit 16. If bit 8 is clear, | ||
125 | one of bits 9-15 must be set, so there will be a carry | ||
126 | into bit 16. Similarly, there will be a carry into bit | ||
127 | 24. If one of bits 24-30 is set, there will be a carry | ||
128 | into bit 31, so all of the hole bits will be changed. | ||
129 | |||
130 | The one misfire occurs when bits 24-30 are clear and bit | ||
131 | 31 is set; in this case, the hole at bit 31 is not | ||
132 | changed. If we had access to the processor carry flag, | ||
133 | we could close this loophole by putting the fourth hole | ||
134 | at bit 32! | ||
135 | |||
136 | So it ignores everything except 128's, when they're aligned | ||
137 | properly. | ||
138 | |||
139 | 3) But wait! Aren't we looking for C, not zero? | ||
140 | Good point. So what we do is XOR LONGWORD with a longword, | ||
141 | each of whose bytes is C. This turns each byte that is C | ||
142 | into a zero. */ | ||
143 | |||
144 | longword = *longword_ptr++ ^ charmask; | ||
145 | |||
146 | /* Add MAGIC_BITS to LONGWORD. */ | ||
147 | if ((((longword + magic_bits) | ||
148 | |||
149 | /* Set those bits that were unchanged by the addition. */ | ||
150 | ^ ~longword) | ||
151 | |||
152 | /* Look at only the hole bits. If any of the hole bits | ||
153 | are unchanged, most likely one of the bytes was a | ||
154 | zero. */ | ||
155 | & ~magic_bits) != 0) | ||
156 | { | ||
157 | /* Which of the bytes was C? If none of them were, it was | ||
158 | a misfire; continue the search. */ | ||
159 | |||
160 | const unsigned char *cp = (const unsigned char *) (longword_ptr - 1); | ||
161 | |||
162 | if (cp[0] == c) | ||
163 | return (void *) cp; | ||
164 | if (cp[1] == c) | ||
165 | return (void *) &cp[1]; | ||
166 | if (cp[2] == c) | ||
167 | return (void *) &cp[2]; | ||
168 | if (cp[3] == c) | ||
169 | return (void *) &cp[3]; | ||
170 | if (4 < sizeof longword && cp[4] == c) | ||
171 | return (void *) &cp[4]; | ||
172 | if (5 < sizeof longword && cp[5] == c) | ||
173 | return (void *) &cp[5]; | ||
174 | if (6 < sizeof longword && cp[6] == c) | ||
175 | return (void *) &cp[6]; | ||
176 | if (7 < sizeof longword && cp[7] == c) | ||
177 | return (void *) &cp[7]; | ||
178 | if (8 < sizeof longword) | ||
179 | for (i = 8; i < sizeof longword; i++) | ||
180 | if (cp[i] == c) | ||
181 | return (void *) &cp[i]; | ||
182 | } | ||
183 | |||
184 | n -= sizeof longword; | ||
185 | } | ||
186 | |||
187 | char_ptr = (const unsigned char *) longword_ptr; | ||
188 | |||
189 | while (n-- > 0) | ||
190 | { | ||
191 | if (*char_ptr == c) | ||
192 | return (void *) char_ptr; | ||
193 | else | ||
194 | ++char_ptr; | ||
195 | } | ||
196 | |||
197 | return 0; | ||
198 | } | ||
199 | #ifdef weak_alias | ||
200 | weak_alias (__memchr, BP_SYM (memchr)) | ||
201 | #endif | ||